Calculate U for LSDA+U: Difference between revisions
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== {{FILE|POSCAR}} == | == {{FILE|POSCAR}} == | ||
For this calculation we will use a 2×2times;2 supercell of AFM-II NiO: | |||
AFM NiO | AFM NiO | ||
4.03500000 | 4.03500000 | ||
Revision as of 17:26, 8 August 2019
Task
In this exercise you will calculate the U parameter for the LSDA+U treatment of Ni d-electrons in NiO using the linear response ansatz of Cococcioni et al..[1]
POSCAR
For this calculation we will use a 2×2times;2 supercell of AFM-II NiO:
AFM NiO 4.03500000 2.0000000000 1.0000000000 1.0000000000 1.0000000000 2.0000000000 1.0000000000 1.0000000000 1.0000000000 2.0000000000 1 15 16 Direct 0.0000000000 0.0000000000 0.0000000000 0.2500000000 0.2500000000 0.2500000000 0.0000000000 0.0000000000 0.5000000000 0.2500000000 0.2500000000 0.7500000000 0.0000000000 0.5000000000 0.0000000000 0.2500000000 0.7500000000 0.2500000000 0.0000000000 0.5000000000 0.5000000000 0.2500000000 0.7500000000 0.7500000000 0.5000000000 0.0000000000 0.0000000000 0.7500000000 0.2500000000 0.2500000000 0.5000000000 0.0000000000 0.5000000000 0.7500000000 0.2500000000 0.7500000000 0.5000000000 0.5000000000 0.0000000000 0.7500000000 0.7500000000 0.2500000000 0.5000000000 0.5000000000 0.5000000000 0.7500000000 0.7500000000 0.7500000000 0.1250000000 0.1250000000 0.1250000000 0.3750000000 0.3750000000 0.3750000000 0.1250000000 0.1250000000 0.6250000000 0.3750000000 0.3750000000 0.8750000000 0.1250000000 0.6250000000 0.1250000000 0.3750000000 0.8750000000 0.3750000000 0.1250000000 0.6250000000 0.6250000000 0.3750000000 0.8750000000 0.8750000000 0.6250000000 0.1250000000 0.1250000000 0.8750000000 0.3750000000 0.3750000000 0.6250000000 0.1250000000 0.6250000000 0.8750000000 0.3750000000 0.8750000000 0.6250000000 0.6250000000 0.1250000000 0.8750000000 0.8750000000 0.3750000000 0.6250000000 0.6250000000 0.6250000000 0.8750000000 0.8750000000 0.8750000000
KPOINTS
Gamma only 0 Monkhorst 1 1 1 0 0 0
[math]\displaystyle{ U = \chi^{-1}-\chi_0^{-1} \approx \frac{1}{0.131333}-\frac{1}{0.492333} = 5.58 \; eV }[/math]
References
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